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questions for programmers interview

category: code [glöplog]
Code:<?php $fizz = file_get_contents('http://www.pouet.net/topic.php?which=8881&page=6 9;); echo str_replace('&quot;<br /> &quot;', '', substr($fizz, strpos($fizz, 'puts(<br') + 23, 554));
@tomaes: It's under the WTFPL.
added on the 2012-07-02 22:59:10 by rrrola rrrola
Tried to do something interesting with your version, but ended up with an unwieldy mess :P

I also updated fizzbuzz.c with 2 new versions, one based on yours.
added on the 2012-07-03 10:08:52 by tomaes tomaes
Earx, the LINQ pretend-SQL is confusing. You can write the same in more standard C-pound syntax (which I prefer):
Code: Enumerable.Range(1, 100).GroupJoin( Enumerable.Range(1, 100).SelectMany( j=>new[] { new { k = j, v = j.ToString() }, new { k = j * 3, v = "Fizz"}, new { k = j * 5, v = "Buzz"}, new { k = j * 15, v = "FizzBuzz"}, } ), i=>i, e=>e.k, (i, l)=>l.First().v);
added on the 2012-07-03 10:16:55 by 216 216
216 sees right through me. in fact, i started with roughly that :-)

#ponce, nice. what language is that?
added on the 2012-07-03 11:29:51 by skrebbel skrebbel
skrebbel: Looks like D.
added on the 2012-07-03 11:38:11 by kusma kusma
Here's an approach that I've not seen yet. :)

Code: #define T .999 #define F float char n[8] = {0}; char *s[] = { "fizz","buzz","fizzbuzz" }; for( i = 0; i++ < range; ){ itoa(i,n,10); printf("%s:",cos((i/15.-(F)(i/15)))>T?s[2]:cos((i/5.-(F)(i/5)))> T?s[1]:cos((i/3.-(F)(i/3)))>T?*s:n); }
added on the 2012-07-03 12:02:39 by tomaes tomaes
Code:#include <stdio.h> #define _USE_MATH_DEFINES #include <math.h> void main() { char* words[] = { "Buzz", "Fizz", "Fizz", "FizzBuzz" }; for(int i = 1; i <= 100; i++) { int k = (int)floor((2*cos(i*M_PI/1.5) + cos(i*M_PI/2.5))+0.5); if(k >= 0) printf("%s\n", words[k]); else printf("%d\n", i); } }
added on the 2012-07-03 12:17:42 by skrebbel skrebbel
wow. eh. great minds think alike, i guess :-)
added on the 2012-07-03 12:18:32 by skrebbel skrebbel
skrebbel: Since timing. :D ("fizz" twice? Mhmm? :P)

Also, I'm done. Not gonna do a whitespace, piet or brainfuck version any time soon. :)
added on the 2012-07-03 12:21:37 by tomaes tomaes
Eh, Since=Nice. Brainfart.
added on the 2012-07-03 12:37:57 by tomaes tomaes
I wonder whether the program would run faster if the modulo operations were replaced by something else, as modulo usually requires division and division is slow.

e.g.

Code:#include <stdio.h> void main() { int i, c3, c5; for (i = 1, c3 = 2, c5 = 4; i <= 100; i++, c3--, c5--) { if (!c5) { if (!c3) { printf ("Fizz"); c3 = 3; } printf ("Buzz\n"); c5 = 5; } else if (!c3) { printf ("Fizz\n"); c3 = 3; } else printf ("%d\n", i); } }
added on the 2012-07-03 16:12:35 by Adok Adok
Division/modulor by a constant can be optimized by a compiler which had some love behind it (like icc, gcc, vcc, clang). Also, modern desktop CPU are no 386 or Z80 :p
meh, 5 s. of googling and voila http://stackoverflow.com/questions/171301/whats-the-fastest-way-to-divide-an-int eger-by-3
Oh, I've noticed BarZoule has already posted a version based on the same idea as mine.
added on the 2012-07-03 16:21:52 by Adok Adok
Python 2.x, the idiomatic edition
Quote:

for i in xrange(1, 101):
if i % 3 == 0:
s = ' fizz'
elif i % 5 == 0:
s = ' buzz'
else:
s = ''

print '%d%s' % (i, s)


Python 2.x, "WTF" edition
Quote:

print ''.join(['%d buzz\n' % (i+1) if (i+1) % 5 == 0 else '%s\n' % x for i, x in enumerate(['%d fizz' % x if x % 3 == 0 else x for x in xrange(1, 101)])])
Adok: Optimizing compilers turn modulo with constant values into long multiplies these days, and multiplies are just as fast as other ops. So no.
added on the 2012-07-03 19:28:52 by kusma kusma
Quote:

int main(int argc, char** argv)
{
char i, j;
signed char buffer[9];
int fizz = 2054842694;
int buzz = 2054845762;

buffer[9] ^= buffer[9];

for (i = 1; i <= 100; i++)
{
buffer[4] = i;
do
{
sprintf(buffer, "%d", buffer[4]);
if (buffer[4] == i)
{
memcpy(buffer + 5, buffer, 3);
buffer[8] = 255;
}

buffer[4] = buffer[9];
for (j = 0; buffer[j] != 0; j++)
{
buffer[4] += buffer[j];
}

buffer[4] -= 3 * j << 4;

if (buffer[4] != i)
{
memcpy(buffer, buffer + 5, 3);
}

if(buffer[8] < 0) {
buffer[8] = j - 1;
}
}
while(buffer[4] >= 10);

switch(buffer[4])
{
case 0:
case 3:
case 6:
case 9:
memcpy(buffer, &fizz, 4);
buffer[8] += 5;
}

buffer[4] = buffer[9];

if (buffer[buffer[8]] == 53
|| buffer[buffer[8]] == 48
)
{
if (strlen(buffer) > 3) {
memcpy(buffer + 4, &buzz, 4);
} else {
memcpy(buffer, &buzz, 4);
buffer[4] = buffer[9];
}
}

puts(buffer);
}

return 0;
}
Guys, please use the [code] tag, not the [quote] one. Quote will eat leading tabs and spaces and you miss out on the monospaced font too.
added on the 2012-07-03 19:59:21 by tomaes tomaes
Actually I think the combination of using proportional fonts and shunning indentation - both of which are not unheard of - suit these programs nicely.
added on the 2012-07-03 20:32:18 by Moerder Moerder
@Optimus: your problem is communication.

1/ your sentences are too long and too complex.

Few people will take the time to understand them as we are in a rat race world.

2/ you don't use paragraphs either.

They are required to structure your thoughts correctly.

3/ If I were you, I would:

a. stop using the 'dirty minds' group name: it makes your mind dirty and so your thoughts

b. spend a lot of time using alternative OS: Linux, Mac OS X, Open Solaris

Use them, to get used to something different than Windows and its mess of interface.

Read their respective documentation.

Read well written books: short books and apply what they say so it'll not stay theory.

What you read and how it is structured, has an impact on your thinking.

Practicing clear your thoughts of doubts: books are full of mistakes,

by practicing your find them and go past them.

c. watch carefully what you eat: mens sana in corpore sano.

Read this and you can find it in Greek of course:

http://www.greekmedicine.net/whos_who/Hippocrates.html

d. challenge yourself to walk 1 hour a day at least.

Walking is the exercise which move the most blood inside your body

and

blood brings nutrients to your cells.

e. Then you'll get confident and will then be able to talk without stress.

If you do all this, and continue doing it, I guarantee you, you'll be soon very confident and will get a job.
My try the Python way :

Code: print list(map((lambda x: "fizz" if x%3==0 else "buzz" if x%5==0 else "fizzbuzz" if x%15==0 else x),range(1,100)))

added on the 2012-07-03 21:25:09 by flure flure
As usual, this question is better solved with HQ9F+ : http://cfs.maxn.jp/neta/HQ9F+.en.html
Alter-native: context?
added on the 2012-07-03 21:57:05 by TLM TLM
Alter-native = EP?
added on the 2012-07-03 23:42:51 by Adok Adok

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